6.03 Calorimetry Lab

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For the first reaction, which is NaOH(s) → NaOH(aq), I would first need to measure out the required .041 moles of NaOH, which would weigh 1.65 grams. I would then measure out 41 milliliters, so that when I mixed the two, my concentration of NaOH in my aqueous solution will be 1M. In all, this should weigh about 41.8 grams when mixed together; however, prior to pouring the NaOH, I will first need to measure the temperature of the water itself with the calorimeter; I will do this at least five times during twenty second intervals. Then I will pour in the NaOH, and measure the temperature again at 20 second intervals until I reach the maximum temperature, which I will be alerted to once the temperature of the solution stops rising and begins …show more content…
I will first measure out the 61mL of the 1M HCl solution. I will then measure the temperature of this solution, again over the course of five intervals, before pouring in the 1M NaOH solution. With the increased amount of water, I will have a slightly larger mass than I had in the original experiment. My new mass will be around 104 grams. After pouring in the 1M NaOH solution, I will again record the temperature of the solution multiple times in twenty second intervals until I have reached the maximum temperature. Then, to find the, ΔH°(solution), I will find difference between the maximum temperature of the solution during the reaction and the temperature of the solution prior to the reaction. I will then multiply this value by 4.18, which is the heat capacity of water in Jules over degrees Celsius times grams. I will then multiply this number again by the total mass of this solution, which is about 104 grams. I will then multiply this number by negative 1 because this answer tells me the ΔH° of the solution/the surroundings, and I want to know the ΔH° of the system, or the ΔH° of