Abc Case Study Answers

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1. For AABbcc their can be 2 gametes produced and the genotypes are ABC and Abc, For AaBBCc there are 4 gametes that can be produced and the genotypes are ABC, A B c, a B C, and aBc. For the last one AaBbCc there are 8 gametes that can be produced and they are ABC,ABc, Abc,aBc, abc, and abc.

2. A. 75% is the probability that a calf born to these parents will be horned. B. 25% that the calf will be hornless.

3. I think that the probability that their child will be a girl who is a non-taster would be around 35%. and the probability that it will be a boy that is a taster would be 55%. The reasoning behind why is because the taster genes are homogygous where as the non-tasters are hetero.

4. A. The expected offspring phenotype between a curly-haireed red bull and a true-breeding straight haired white cow would be Rrss for all of the gametes. This would then leave the straight haired cows having WWSS. Concluding that the cross breed for the roans would most likely be RWSs.
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The male is most likely going to be Ss Bb The reason why is because the males are solid and black so this means that they are the one that carry that dominant gene within them. Also the child needs the recessive gene from each parent to determine the outcome of the color.
Where as the female is totally red so she has to have both of the recessive genes to be a certain type. The female is going to be Ss bb.

6. The reason why females can only be the ones with a tortoiseshell is because of the chromosomes that are linked with the reason behind why. There is a huge difference males only have one x chromosome and females have 2 so they have more of a chance behind their determination of color which takes role on the