Absorption Spectroscopy: Beer-Lambert Law Essay

Words: 1054
Pages: 5

Absorption Spectroscopy

Author: Cesar M. Lemas

Lab Partners: Jahnnan Jayesh Patel, Myong Ho Lee & Salem Alsaif

Instructor: Jordan Andrew Mudery

Chem 151, Section 7D

Date Work Performed: October 18th 2012

Date Report submitted: October 25th 2012

Absorption spectroscopy is a practical way to find what the light absorption of a substance is, and whit this data combining the Beer’s law equation you can determine the concentration of different things in a solution, in this case using a orange Gatorade looking the concentration of its dye which is yellow dye #6 and what amount of this Gatorade sample is needed to kill someone. The outcomes in this experiment were that the yellow dye #6 concentration is
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The calculations done in this experiment were to get the concentration of the stock dye dilutions, the concentration of the dye in the Gatorade using Beer’s law sample and the LD50 of the Gatorade. Concentration = (Dye amount)/(Total amount of Solution)
C = (1.0 ml of yellow dye #6)/(11ml of water+dye)
C = 3.7x10-6 M Absorption = εbC
C =Absorption/εb
C = 0.116/(21657(1))
C = 5.356x10-6 M LD50= C x MM=g/L then with LD50 of the stock dye x L/g to get the Liters per kilogram needed to kill someone.
5.356x10-6 M x 4.10x10-5MM = 0.0024226259 g/L
6g/Kg x 1L/0.0024226259g=2476.651471 L/kg
And then because the solution used was diluted to 1/10 ratio we need to multiply it by 9.09 which is the percentage of dye in the solution. And the result was 22,515 L / Kg.

Wrap Up Discussion

What is the dye content of your sample? How much of the food must you consume to reach an LD50 exposure..
R: Yellow dye #6, 22,515 L / KG