2. The percentage of the first pattern of heredity is expected to be 75%T and 25%t. The genotype would be 25% homozygous dominant, 50% heterozygous dominant, and 25% homozygous recessive. The phenotype would be 3 to 1, 3 tall plants and 1 short plant. For the second pattern of heredity, the percentage is 50%T and 50%t. The genotype would be 50% homozygous dominant and 50% heterozygous dominant. The phenotype would be 4 tall plants which is 100% tall plants.

3. The percentages from class 1 is 80% and 20%. The expected percentage of class 2 is 75% and 25%, therefore they were not similar.

4. The percentages from class 1 results is 74% and 26%. The expected percentage of class 2 was 75% and 25%, therefore they were similar.

5. Since the expected results and our results were similar, I found that the pattern of heredity is trustworthy for any situation.

Punnett Squares for #2:

Tt*Tt

TT*Tt

Conclusion: My claim is that desultory parent genes give more desultory genes for the progeny that are opted for. The desultory genes that were chosen for the offspring are following a common ratio. My hypothesis is supported because the desultory combinations led to unexpected pairs, however, followed a similar ratio to all other trials. My evidence is that the expected percentages were similar to the trials that I did and what the class had. My results is 80% and 20%, and the expected is 75% and 25%, which was similar in quantity. Similarly, the class results also had the same results, the expected is also 75% and 25%, and the class had conducted up to 74% and 26%. These trials would make the…