Question/Purpose:

To find the relationship between maximum static friction and normal force.

Experimental Hypothesis:

The relationship between maximum static friction and normal force is a direct positive linear relationship.

Drawings/Diagrams:

Experimental Setup

Data:

**Mass of Block: 95.8

Experimental Data Mass (kg) | Fsmax (N) | Fnorm (N) | Fsmax/Fnorm (N/N) | .0958 | .5665 | 0.939 | 0.603 | .1458 | .5964 | 1.429 | 0.4174 | .1958 | .6562 | 1.919 | 0.3419 | .2958 | .7938 | 2.899 | 0.2738 | .5958 | .9195 | 5.839 | 0.1575 | 1.0958 | 1.037 | 10.739 | 0.0965 |

Y=0.0868X+0.5727

Interpolation Predicted Fnorm (N) | Predicted Fsmax (N) | Actual Fnorm (N) | Actual Fsmax | 3.879 | .7576 | 3.879 | .7679 |

Extrapolation Predicted Fnorm (N) | Predicted Fsmax (N) | Actual Fnorm (N) | Actual Fsmax | 12.70 | 1.178 | 12.70 | 1.173 |

Avg. Fsmax/Fnorm = (∑Fsmax/Fnorm)/# of measurements

Avg. Fsmax/Fnorm= (1.8901)/6

Avg. Fsmax/Fnorm = 0.04150

% Difference=|(Meas1-meas2)/(1/2(m1+m2))|*100

% Difference = |(.04150-.04768)/(1/2(.04150+.04768))|*100

%Difference = 1.38%

Precision of Measuring Devices:

Mass Balance-+/- 0.00001 kg

Scientific Concepts:

Conclusion: Our experimental results led us to conclude that our data does support our hypothesis. We found that the relationship between the values of Fsmax and Fnorm is linear and is defined by the following equation:

Fsmax=0.04768(Fnorm)+0.5727

Using our data, we graphed the relationship between Fsmax and Fnorm and calculated the best fit line, which was then translated…