Job Satisfaction is a Post Hoc Phenomenon Essay

Submitted By anthonyfra85
Words: 752
Pages: 4

PROBABILITY DISTRIBUTIONS
One’s attitude towards their job is reflected in his/her job satisfaction. This “quantity” can be measured various ways(e.g. intrinsic/extrinsic). Nevertheless, job satisfaction is a post hoc phenomenon. Statistics is used throughout the business world to evaluate both financial and decision-making risks. Every decision made by management is accompanied by a chance for failure, therefore, statistical analysis is conducted formally ("math") and informally (i.e. "I hope"). Math responses are preferred, however, they do require advanced training such as college courses.

· What is the distribution of individuals by gender?
From the data set we find that there are a total of 11 male responses out of total 25 responses

Therefore % males = 11 / 25 = 0.44 * 100 = 44%

Out of the same set of responses, there is a total of 14female Therefore % females = 14 / 25 = 0.56 * 100 = 56%

· What is the “tenure with company” distribution by gender?

From the data we observe that there are 11 males: 5 with code 1 meaning that they stay in the company for less than 2 years 2 with code 2 meaning that they stay in the company for 2 to 5 years.” 4 with code 3 meaning that they stay in the company over 5 years” So, the “tenure with company” distribution by male is: 2/11=18.2% of 8 males stays in the company for 2 to 5 years. 4/11=36.4% of 8 males stays in the company over 5 years; 5/11=45.5% of 8 males stays in the company for less than 2 years.

From the data we observe that, there are 14 females: 6 with code 1 meaning that they stay in the company for less than 2 years 5 with code 2 meaning that they stay in the company for 2 to 5 years.” 3 with code 3 meaning that they stay in the company over 5 years” So, the “tenure with company” distribution by male is 5/14=35.7% of 17 females stay in the company for 2 to 5 years. 3/14=21.4% of 17 males stay in the company over 5 years; 6/14=42.9% of 17 females stay in the company for less than 2 years.

· The percentage of the participants in each department are as follows:
Therefore % of the survey participants are in HR department = 5/ 25 = 0.20*100=20%

Total no of participants form department 2 (IT) = 13

Therefore % of the survey participants are in HR department = 13 / 25 = 0.52*100=52%

Total no of participants form department 3 (ADMIN) = 10

Therefore % of the survey participants are in HR department = 7 / 25 = 0.25*100=28%

· This is the sample mean for extrinsic value by gender:
For female the sample mean for extrinsic value is given by

[pic] = sample mean = [pic]

For males the sample…