Nt1310 Unit 2 Lab Report

In the experiments I conducted, I concluded that the mathematical relationship between frequency and time period is inverse. When looking at my data, I noticed that as the time period increased, the frequency would decrease. An example of the inverse relation can be seen in each one of my data tables, but I will show one example from Part B of my experiment. For 33.5 centimeters, the time period was roughly 1.15 seconds and the average frequency was 0.87 Hz and at 49 centimeters the time period was 1.37 seconds and the average frequency was 0.73. This shows an inverse relationship because as the time period increased, the average frequency decreased. After making the graph, my final equation ended up being: time period = (-1.63 x average frequency) + 2.529 (which is my y-intercept).
In Part …show more content…
For my smallest amplitude of 10 degrees, the time period was 1.53 seconds. For 20 degrees, the time period was 1.54 seconds, and for my biggest amplitude of 30 degrees, the time period went down to 1.51 seconds. This data does not show an inverse or direct relationship between amplitude and the time period, but the change in the time period is not significant, making my line of best fit a straight line. The final equation for Part A ended up being: time period = (-0.0008 x amplitude) + 1.536 (which is my y-intercept). In Part B, I realized that as I increased the length of my string, my time period increased, making the relationship between the length and the time period a direct relationship. For my shortest length of 27 centimeters, my time period was roughly 1 second and after increasing my string length to 59

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