Nt1320 Unit 4

Question Content Description and the reason behind the selection
(ACARA, n.d.) Answer Method Alternative Method 2 The problem requires counting small collections of Australian coins (ACMNA034). D Count money.
$1.00+$0.20=$1.20;
$1.20 +$0.10=$1.30;
$1.30+$0.05=$1.35. Coins Figure 1. Sets of Australian coins.
(ACARA, 2011)

Add all 5c: 20+4+2+1=27.
Multiply 5c by 27
Total amount=27×5c=135c=$1.35.

4 The question involves simple subtraction using mental and written strategies (ACMNA030); alternatively, it requires rearranging collections of hundreds (ACMNA028). D Use subtraction, subtracting 10 at a time. 542-10=532; 532-10=522; 522-10=512; …show more content…
Next, of each shape, lay its parts over each other, see if they have the same area. Only option D has 4 equal quarters.

Cut-outs of shapes Figure 4. Cut-outs of shapes (ACARA, 2011)

14 The question involves identifying number sequences that increase by fours (ACMNA026). B Use tally and analyse all patterns by adding 4.

Use number lines and examine all patterns to identify the right number pattern that increases by fours.

15 Students use different mental and written strategies to identify correct option (ACMNA030). A Use tally to equate all number sentences to find the correct …show more content…
A
40–13=27
40–10=30;
30-3=27

23 Students recall multiplication operation to solve division facts (ACMNA056). 9 Tony gets $15 for 3 cars.
He gets $1 for 3/15 cars or equal to 1/5cars.
Use the amount of 1 car and multiply with $45;
1/5×45=9 cars. For 3cars Tony gets $15. Use array as 3 rows of 5 to get the amount per car; which means $(15÷3) =$5. Each row represents $5 per car; hence: form rows until $45 is spent: $45/5=9cars.
24 Students identify missing number (ACMNA035). 17 Take 42 and use counters to take away 25 to determine the missing number. Count backwards in ten frames from 25 to 42: 25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42. 27 Students determine missing element (ACMNA035). 7 Use counters and take away 6 from 20.

Now, divide 14 by 2. Result: 14/2=7. x is an unknown number. Double of x is 2x.
Add 6 to 2x: 2x+6;
Now 2x+6=20 or, 2x=20-6=14

→x=14/2=7
30 Students identify missing number (ACMNA035) A In 4years Jodie’s age will be 20years. Steve’s current age:
(½ ×20)-4=10-4=6years.

Use 20 counters and take away half to calculate Steve’s age in 4 years. Then take away 4 counters to count Steve’s current

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