Hypothesis: Focus the particular senior high school temperature of a metal its distinguishing proof. The class has these obscure alloys: Aluminum, Copper, Lead, Tin can and Zinc. Our gathering had Tin.
Materials and equipment: obscure metallic element specimen, parity, thermometer, Styrofoam container with crown, cool water, boiling hot water.
1. The mass of the unfilled glass and top was measured by the parity.
2. The mass of the cover and mug with enough chilly water interior to cover the metal example was measured by the equalization.
3. The beginning temperature of the water was recorded by utilizing the thermometer.
4. A metal example was immediately recovered from the simmering hot water shower and put into the icy water in the container.
5. The cover was put on the field glass before a considerable measure of hotness got away into the nature's greensward.
6. The temperature of the high temp water was recorded.
7. The thermometer was embedded into the water in the container and the most elevated railroad quality was recorded.
8. The metal specimen was gotten dry and its mass was measured by the equalization.
Our group’s data
Mass of the empty cup and lid 3g
Mass of the lid and cup with cold water
Mass of the water
Mass of the metal
Temperature of hot water bath
(Initial temperature of the metal)
Initial temperature of the water
Final temperature of the water
The thermal energy gained by the water with our group’s data
Q = mwater× (4180 J/kg °C) × ∆Twater =0.1031kg×(4180 J/kg °C) ×(23°C-21°C) =861.9J
The thermal energy lost by the metal should be equivalent to this:
-Q = mmetal × cmetal × ∆Tmetal
-861.9J= mmetal × cmetal × ∆Tmetal
The c is calculated
-861.9J= 0.071× cmetal ×(23°C-92°C) cmetal=176.4 J/kg °C
Table 1: accepted specific heat capacity of metals
Accepted c (J/kg* k)
1- Our ascertained particular high temperature limit of the metal was 176.4 J/kg °c, which is a quality in the middle of Lead and Tin. Since our information is all the more closer to the acknowledged c of Tin which is 210, we think our metal was Tin.
Table 2: Class Results
Calculated c (J/kg*k)
Our group had Tin and the % error is: