Titration Lab Report Discussion

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The purpose of the experiment is to use titration as a tecnique in order to determine the value of a created molarity of the titrant(NaOH), and then determine the value of an unknown value of an analyte (KHP). The molarity value for the first test was 0.1017 M 8.9710-4M, which was very percise and accurate. The percentage of pottasium hydrogen phthalate(KHP) determined for the unknown as 30.705%, while the actual percentage was 30.48%. These results were accurate but they were not percise because of errors that occured during the titration process.

Titration is a common tool used in order to find the concentration or amount of a substance in a solution. This method is used to test many things in day to day life. For example, titration is …show more content…
To do this, one substance, called the titrant, is added to another substance, which is called the analyte, until a reaction has been completed. For the titrant and the analyte, one must be an acid and one must be a base and either the titrant or the analyte must be known in order to determine the amount or concentration of the other. This is possible because the molar amount of the titrant needed in order to complete the entire reaction can be found by using a balanced chemical equation between the titrant and analyte. For the reaction to be complete, all available ionizabe hydrogen ions of one solutions must react with all available hydrogen ions in order to form water molecules. To be able to tell that the reaction is complete, there has to be a color change by using an indicator, or another indication. It is important to have a good primary standard to compare results to and affirm the accuracy of the experiment. A good primary standard such as potassium acid phthalate, is good because it is air stable and solid. This makes it easier to obtain an accurate weight. However, sodium hyrdoxide is not a good primary standard because it absorbs water from the air causing it to be accurately weighed, as well as carbon dioxide, which forms sodium carbonate and therefore the amount of sodium hyroxide is
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