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midpoint formula

circle

prove right triangles using isosceles if 2 sides have the same length diagonals have the same midpoint if they bisect each other slope of a line

point slope form

general form

parallel and perp lines are perpendicular if

vert.

horiz.

, parallel if slopes are equal

completing the square quadratic

Chapter 1 it is a function if there is one input, and one or more outputs

domain: “is there anything i can't stick in”, make equal to 0, when in radical it can be 0 and + #, but no , so set inside odd/even/neither: even f(x)=f(x), same on left as right of yaxis, odd f(x)=f(x), same upside down as right side up neither: graph looks same above xaxis as it does below asymptotes: y=b horizontal,

=b or

=b, vertical asymptote x=a

inverse: original, then solve for x,switch x and y. translations: horizontal: 1.

a translation to the right by c units

2.

a translation to the left by c units

3. across the xaxis 4. stretches and shrinks

a stretch by a factor of c if c>1, shrink by a factor of c if c<1

Vertical

1.

a translation up

2.

a translation down

3. across the yaxis

, for range: graph

4.

equations: : circumferenc of circle

simple interest I=Prt compound interest A=P(1+r/n)^nt

Chapter 2

polynomial function: where n is degree, and a is leading coefficient, an vertex form of a quad func: f(x)=a(xh)^2+k (h,k) axis x=h, where h=b/2a and k=cah^2 if…