formal lab Essay

Submitted By carmenplacencia
Words: 395
Pages: 2

750.06 ×(1 atm)/(760 mm)=0.9574 atm. To calculate the moles of magnesium 0.0414 g of Mg×(1 mole Mg)/(24.31 g Mg)=0.00170 moles of Mg. The calculation for moles of H2
Accurate data was important in this experiment since calculations led to the other answers. If the calculations were not accurate the whole data would be incorrect. The experiment was conducted by the formula Mg(s) +2HCl(aq) → H2(g) + MgCl2(aq). The magnesium reacted when the hydrochloric acid was added and created the hydrogen gas.
750.06 ×(1 atm)/(760 mm)=0.9574 atm. To calculate the moles of magnesium 0.0414 g of Mg×(1 mole Mg)/(24.31 g Mg)=0.00170 moles of Mg. The calculation for moles of H2
Accurate data was important in this experiment since calculations led to the other answers. If the calculations were not accurate the whole data would be incorrect. The experiment was conducted by the formula Mg(s) +2HCl(aq) → H2(g) + MgCl2(aq). The magnesium reacted when the hydrochloric acid was added and created the hydrogen gas.
750.06 ×(1 atm)/(760 mm)=0.9574 atm. To calculate the moles of magnesium 0.0414 g of Mg×(1 mole Mg)/(24.31 g Mg)=0.00170 moles of Mg. The calculation for moles of H2
Accurate data was important in this experiment since calculations led to the other answers. If the calculations were not accurate the whole data would be incorrect. The experiment was conducted by the formula Mg(s) +2HCl(aq) → H2(g) + MgCl2(aq). The magnesium reacted when the hydrochloric acid was added and created the hydrogen gas.
750.06 ×(1 atm)/(760 mm)=0.9574 atm. To calculate the moles of magnesium 0.0414 g of Mg×(1 mole Mg)/(24.31 g Mg)=0.00170…